Question

If dot C moves to position 5 (60 meters), what is its average velocity during these 5 seconds? A) 10 m/s B) 11 m/s C) 12 m/s D) 13 m/s

Answer 1

c) 12 m/s because 60 m ÷ by 5sec equals 12m/s

Answer 2

C) 12 m/s

Step-by-step explanation:

As we know that average velocity is given as ratio of displacement and time

so here we can say

`v_(avg) = (displacement)/(time)`

now we have

`displacement = 60 meter`

`time = 5 seconds`

now as per above formula we have

`v_(avg) = (60)/(5)`

`v_(avg) = 12 m/s`

so the average velocity must be 12 m/s