197k views
0 votes
A waitress sold 10 ribeye steak dinners and 18 grilled salmon dinners, totaling $590.39 on a particular day. anither day she sold 22 ribeye steak dinners and 9 grilled salmon dinners, totaling $583.49. how much did each type of dinner cost?

a) the cost of ribeye steak dinners is $__

b) the cost of salmon dinners is $__

1 Answer

3 votes

Answer:

a) The cost of ribeye steak dinners is $ 16.96.

b) The cost of grilled salmon dinners is $ 23.37.

Step-by-step explanation:

Let the cost for ribeye steak dinners be m and cost for grilled salmon dinners be n.

A waitress sold 10 ribeye steak dinners and 18 grilled salmon dinners, totaling $590.39 on a particular day.

So, we have

10 m + 18 n = 590.39 -------equation 1

Another day she sold 22 ribeye steak dinners and 9 grilled salmon dinners, totaling $583.49

So, we have

22 m + 9 n = 583.49 -------equation 2

equation 2 x 2

44 m + 18 n = 1166.98 -------equation 3

equation 3 - equation 1

44 m + 18 n - ( 10 m + 18 n ) = 1166.98 - 590.39

m = 16.96 $

Substituting in equation 1

22 x 16.96 + 9 n = 583.49

n = 23.37 $

a) The cost of ribeye steak dinners is $ 16.96.

b) The cost of grilled salmon dinners is $ 23.37.

User EarlyPoster
by
8.8k points