Answer:
(0, 1 )
Explanation:
2x + 5y = 5 → (1)
- 3x + 7y = 7 → (2)
to eliminate y multiply (1) by 7 and (2) by - 5 , then add the result
14x + 35y = 35 → (3)
15x - 35y = - 35 → (4)
add (3) and (4) term by term to eliminate y
29x + 0 = 0
29x = 0 ⇒ x = 0
substitute x = 0 into (1) and solve for y
2(0) + 5y = 5y
0 + 5y = 5
5y = 5 ( divide both sides by 5 )
y = 1
solution is (0, 1 )