Explanation:
let's do a prime factor analysis :
156 ÷ 2 = 78
78 ÷ 2 = 39
39 ÷ 2 no
39 ÷ 3 = 13
13 ÷ 3 no
13 ÷ 5 no
13 ÷ 7 no
13 ÷ 11 no
13 ÷ 13 = 1 finished
therefore,
156 = 2×2×3×13
1 and 156 are default factors (1 and the number itself are factors for every number).
all the other factors are combinations of these prime factors :
2×2 = 4
2×3 = 6
2×2×3 = 12
2×13 = 26
2×2×13 = 52
3×13 = 39
2×3×13 = 78
so, no he should not stop there, he has to include also the quotients as factors, and overall find all the prime factor combinations.
all the factors are
1, 2, 3, 4, 6, 12, 13, 26, 39, 52, 78, 156