87.9k views
0 votes
Given a set S = {a, b, c}, find the subsets of two elements (r = 2) when 1. repetition is allowed and order matters. 2. repetition is not allowed but order matters. 3. repetition is not allowed and order does not matter. 4. repetition is allowed but order does not matter. 5. Show all the permutations (order matters) of the three elements in set S.

User Nischi
by
6.3k points

2 Answers

2 votes

Final answer:

The question involves finding subsets of two elements from a set under different conditions of repetition and order and listing all permutations of three elements. We derive several possible combinations for each case based on these criteria.

Step-by-step explanation:

To enumerate the subsets of two elements from set S = {a, b, c}, we need to consider different scenarios depending on whether repetition is allowed and whether order matters.

  1. Repetition allowed, order matters: We can have aa, ab, ac, ba, bb, bc, ca, cb, cc.
  2. Repetition is not allowed, order matters: We can have ab, ac, ba, bc, ca, cb.
  3. Repetition is not allowed, order does not matter: We can have ab, ac, bc.
  4. Repetition is allowed but order does not matter: This is not applicable because if repetition is allowed, the notion of order must be considered to differentiate the subsets.
  5. All permutations of the three elements (abc, acb, bac, bca, cab, cba) are the six different ways we can arrange the elements of set S.

Each of these cases applies different combinatorial rules, which change how we count the number of outcomes based on the constraints imposed by repetition and order.

User Oxilumin
by
6.2k points
2 votes

i am not good with math but b i think.


User Sanah
by
6.1k points