Question

What is the reaction quotient, Q, for this system when [N2] = 2.00 M, [H2] = 2.00 M, and [NH3] = 1.00 M at 472°C?

Answer 1

the first answer is 0.0625

the second one is Q < Keq

Answer 2

Answer : The value of reaction quotient, Q is 0.0625.

Solution : Given,

Concentration of
`N_2` = 2.00 M

Concentration of
`H_2` = 2.00 M

Concentration of
`NH_3` = 1.00 M

Reaction quotient : It is defined as a concentration of a chemical species involved in the chemical reaction.

The balanced equilibrium reaction is,

`N_2+3H_2\rightleftharpoons 2NH_3`

The expression of reaction quotient for this reaction is,

`Q=([Product]^p)/([Reactant]^r)\\Q=([NH_3]^2)/([N_2]^1[H_2]^3)`

Now put all the given values in this expression, we get

`Q=((1.00)^2)/((2.00)^1(2.00)^3)=0.0625`

Therefore, the value of reaction quotient, Q is 0.0625.