Answer:
n(B) = 45
Explanation:
n(A U B) = 65 size of all elements in set A or set B or both
n(A ∩ B) = 22 size of all elements common to sets A and B
n(A - B) = 30 size of all elements in set A but not set B
n(A) = n(A - B) + n(A ∩ B) the total number of elements in set A is the
the number of elements in A but not B plus
the number of elements common to A and B
= 30 + 22 = 52
n(AUB) = n(A) + n(B) - n(A∩B)
So n(B) = n(AUB) - n(A) + n(A∩B)
= 65 - 52 + 22
= 45