Question

The only solution for the equation x^2+bx +16=0 is x=4 what is the value of B

Answer 1

The value of b=-8

Explanation:

Given : The only solution for the equation
`x^2+bx +16=0` is x=4.

To find : What is the value of b ?

Solution :

The equation
`x^2+bx +16=0`

The only solution of the equation is x=4.

So, Substitute the value of x in the equation

`(4)^2+b(4) +16=0`

`16+4b+16=0`

`4b+32=0`

`4b=-32`

`b=-(32)/(4)`

`b=-8`

Therefore, the value of b is -8.

Answer 2

x^2+bx +16=0 is x=4

x^2+bx +16=(x-4)^2

x^2+bx +16=(x^2 -8x+16)

b=-8