Question

X^2+3x-3=0 completing the square (use radical) find x

Answer 1

`x^2 + 3x - 3 = 0`

`x^2 + 3x = 3`

`x^2 + 3x + \left( (3)/(2) \right)^2 = 3 + \left( (3)/(2) \right)^2`

`\left(x + (3)/(2) \right)^2 = (12)/(4) + (9)/(4)`

`\left(x + (3)/(2) \right)^2 = (21)/(4)`

`x + (3)/(2) = \pm (√(21))/(2)`

`x + (3)/(2) = (√(21))/(2)` or
`x + (3)/(2) = -(√(21))/(2)`

`x = (√(21))/(2) - (3)/(2)` or
`x = -(√(21))/(2) - (3)/(2)`