Question

An air mattress is filled with 16.5 moles of air. The air inside the mattress has a temperature of 295 K and a gauge pressure of 3.5 kilopascals. What is the volume of the air mattress?

The volume of the air mattress is__liters.

Answer 1

PV=nRT
3.5×X=16.5×0.082×295
X= 114 L
The volume of the air mattress is 114 liters.

Answer 2

Step-by-step explanation:

According to ideal gas equation, product of pressure and volume equals n times R times T.

Mathematically, PV = nRT

where P = pressure

V = volume

n = number of moles

R = gas constant

T = temperature

Therefore, it is given that no. of moles is 16.5 mol, pressure is 3.5 kilopascal equals 0.035 atm (as 1 Kpa = 0.01 atm), temperature is 295 K and R = 0.082
`LatmK^(-1)mol^(-1)`.

Hence, calculate the volume as follows.

PV = nRT

`0.035 atm * V = 16.5 mol * 0.082 L atmK^(-1)mol^(-1) * 295 K`

V =
`(399.135 L atm)/(0.035 atm)`

= 11403.85 L

Hence, we can conclude that the volume of the air mattress is 11403.85 liters.