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Suppose the ages of multiple birth (3 or more babies) are normally distributed with a mean age of 31.7 years and a standard deviation of 5.2 years. What percent of these mothers are between the ages 30-35

User MrGoofus
by
6.3k points

1 Answer

2 votes

Answer:

The percent of these mothers are between the ages 30-35 is 36.53%

Explanation:

we are given

mean of age =31.7 years


\mu=31.7

standard deviation of 5.2 years


\sigma=5.2

For age=30 years:

x=30

we can find z-score


z=(x-\mu)/(\sigma)

we can plug values


z=(30-31.7)/(5.2)


z=-0.32692

For age=35 years:

x=35

we can find z-score


z=(x-\mu)/(\sigma)

we can plug values


z=(35-31.7)/(5.2)


z=0.63462

now, we can use normal distribution table


P(-0.32692<z<0.63462)=0.3653

now, we can find percentage


=0.3653* 100

=36.53%


User BradByte
by
6.9k points
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