Question

Q1-Write Lewis diagram for a)Ne,b)Sb(Z=51),c)Rn,d)a neutral atom with 9 electrons

Answer 1

Explanation: Lewis structure is defined as the structure in which the element is shown with its valence electron represented as dots.

Valence electrons are the electrons present in the last shell.

• For Ne: The atomic number is 10. Valence electronic configuration is
  `[He]2s^22p^6`

Number of valence electrons = 8

• For Sb: The atomic number if 51. Electronic configuration is
  `[Kr]4d^(10)5s^25p^3`

Number of valence electron = 5

• For Rn: The atomic number is 86. Electronic configuration is
  `[Xe]4f^(14)5d^(10)6s^26p^6`

Number of valence electrons = 8

• For a neutral atom with 9 electrons : The atomic number for this element is 9 and the element is Fluorine (F). Electronic configuration is
  `[He]2s^22p^5`

Number of valence electrons = 7

The lewis structures of all the elements are shown in the image attached.