187k views
24 votes
F(x) = 3r2 + 12x + 5

What is the value of the discriminant of f?
D
How many distinct real number zeros does
f(x) have?

User Nubbel
by
9.1k points

1 Answer

8 votes

Answer:

The value of the discriminant is 84.

i.e. b²- 4ac = 84

As

b²- 4ac > 0

Therefore, there are two distinct real number zeros.

Explanation:

We know that the discriminant of the quadratic equation ax²+bx+c=0 is equal to b²- 4ac.

We also know that:

  • When b²- 4ac = 0 there is one real root.
  • When b²- 4ac > 0 there are two real roots.
  • When b²- 4ac < 0 there are two complex roots.

We are given

f(x) = 3x² + 12x + 5

comparing with the quadratic function ax²+bx+c=0

a = 3, b = 12, c = 5

Discriminant = b²- 4ac

= (12)²-4(3)(5) ∵ a = 3, b = 12, c = 5

= 144 - 60

= 84

Thus, the value of the discriminant is: 84

As

b²- 4ac > 0

Therefore, there are two distinct real number zeros.

User Rockbar
by
8.2k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories