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24 votes
F(x) = 3r2 + 12x + 5

What is the value of the discriminant of f?
D
How many distinct real number zeros does
f(x) have?

User Nubbel
by
4.7k points

1 Answer

8 votes

Answer:

The value of the discriminant is 84.

i.e. b²- 4ac = 84

As

b²- 4ac > 0

Therefore, there are two distinct real number zeros.

Explanation:

We know that the discriminant of the quadratic equation ax²+bx+c=0 is equal to b²- 4ac.

We also know that:

  • When b²- 4ac = 0 there is one real root.
  • When b²- 4ac > 0 there are two real roots.
  • When b²- 4ac < 0 there are two complex roots.

We are given

f(x) = 3x² + 12x + 5

comparing with the quadratic function ax²+bx+c=0

a = 3, b = 12, c = 5

Discriminant = b²- 4ac

= (12)²-4(3)(5) ∵ a = 3, b = 12, c = 5

= 144 - 60

= 84

Thus, the value of the discriminant is: 84

As

b²- 4ac > 0

Therefore, there are two distinct real number zeros.

User Rockbar
by
4.6k points