Given:
Volume of O2 , V = 3.90 L
Temperature of O2, T = 273 K
Pressure P = 1.00 atm
To determine:
Molecules of O2
Step-by-step explanation:
From Ideal gas law-
PV = nRT
where n = number of moles of O2
R = gas constant = 0.0821 L atm/mol-K
n = PV/RT = 1*3.90/0.0821*273 = 0.1740 moles of O2
1 mole of O2 contains 6.023 * 10²³ molecules
0.1740 moles of O2 corresponds to :
=6.023 * 10²³ molecules*0.1740 moles of O2/1 mole of O2
= 1.048 *10²³ molecules of O2