Question

If moles and pressure are constant, what is the volume of decane gas at 7°C if 23 mL of decane gas has a temperature of 43K

Answer 1

According to Charles' law for ideal gases, at constant pressure, the volume of a given mass and moles of gas is directly proportional to its temperature in the Kelvin scale.

Therefore,

`(V1)/(T1) = (V2)/(T2)`

Here,

V1 = Initial volume of decane gas = 23 mL

T1 = Initial temperature of decane gas = 7 degree C = ( 7 + 273.15) K = 280.15 K.

T2 = Final temperature of decane gas = 43 K

V2 = Final volume of decane gas = ?

`V2 = ((V1)(T2))/(T1) =  ((23)(280.15))/(43) = 149.8 mL`

The required volume of decane gas is 149.8 mL.