Question

How many grams of Pb are contained in a mixture of 0.135 kg each of PbCl(OH) and Pb2Cl2CO3?

Answer 1

Hey there!:

Given the mass of PbCl(OH) :

0.135 Kg = 0.135 Kg*(1000g / 1Kg) = 135 g

Molecular mass of PbCl(OH) = 207+35.5+16+1 = 259.5 g / mol

Atomic mass of Pb = 207 g/mol

Hence mass of Pb in 135 g PbCl(OH) :

(207 g Pb / 259.5 g PbClOH) * 135g PbClOH =

0.79768 * 135 => 107.68 g of Pb

For Pb2Cl2CO3 :

Given the mass of Pb2Cl2CO3 :

0.135 Kg = 0.135 Kgx(1000g / 1Kg) = 135 g

Molecular mass of Pb2Cl2CO3 = 2*207+2*35.5+12+3*16 = 545 g / mol

Mass of Pb present in 1 mol (=545 g / mol) of Pb2Cl2CO3 = 2*207 = 414 g

Hence mass of Pb in 135 g Pb2Cl2CO3:

(414 g Pb / 545 g PbClOH) * 135g PbClOH =

0.75963 * 135 => 102.55 g of Pb2Cl2CO3

Hope that helps!

Answer 2

Answer: Mass of lead in
`PbCl(OH)` is 107.74 g and mass of lead in
`Pb_2Cl_2CO_3` is 103.6 g

Step-by-step explanation:

To calculate the number of moles, we use the equation:

`\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}` .....(1)

• For PbCl(OH):

Given mass of PbCl(OH) = 0.135 kg = 135 g (Conversion factor: 1 kg = 1000 g)

Molar mass of PbCl(OH) = 259.66 g/mol

Putting values in equation 1, we get:

`\text{Moles of PbCl(OH)}=(135g)/(259.66g/mol)=0.52mol`

In 1 mole of PbCl(OH), 1 mole of lead, 1 mole of chlorine, 1 mole of hydrogen and 1 mole of oxygen atoms are present.

Moles of lead =
`(1* 0.52)=0.52mol`

Calculating the mass of lead in PbCl(OH) by using equation 1, we get:

Molar mass of lead atom = 207.2 g/mol

Moles of lead atom = 0.52 moles

Putting values in equation 1, we get:

`0.52mol=\frac{\text{Mass of lead atom}}{207.2g/mol}\\\\\text{Mass of lead atom}=107.74g`

Mass of lead atom = 107.74 g

• For
  `Pb_2Cl_2CO_3`:

Given mass of
`Pb_2Cl_2CO_3` = 0.135 kg = 135 g

Molar mass of
`Pb_2Cl_2CO_3` = 545.3 g/mol

Putting values in equation 1, we get:

`\text{Moles of }Pb_2Cl_2CO_3=(135g)/(545.3g/mol)=0.25mol`

In 1 mole of
`Pb_2Cl_2CO_3`, 2 moles of lead, 2 moles of chlorine, 1 mole of carbon and 3 moles of oxygen atoms are present.

Moles of lead =
`(2* 0.25)=0.50mol`

Calculating the mass of lead in
`Pb_2Cl_2CO_3` by using equation 1, we get:

Molar mass of lead atom = 207.2 g/mol

Moles of lead atom = 0.50 moles

Putting values in equation 1, we get:

`0.50mol=\frac{\text{Mass of lead atom}}{207.2g/mol}\\\\\text{Mass of lead atom}=103.6g`

Mass of lead atom = 103.6 g

Hence, mass of lead in
`PbCl(OH)` is 107.74 g and mass of lead in
`Pb_2Cl_2CO_3` is 103.6 g