Question

Can someone be ever so kind and help me with 20-24

Answer 1

`20.\\15cd=(3)(5)cd\\25cd^3=(5)(5)cddd\\\\LCM(15cd,\ 25cd^3)=(3)(5)(5)cddd=75cd^3\\\\21.\\5g^2h^3=5gghhh\\19g^3h=19gggh\\\\LCM(5g^2h^3,\ 19g^3h)=(5)(19)ggghhh=95g^3h^3\\\\23.\\\\Multiples\ of\ 12:\ 0,\ 12,\ \boxed{24},\ 36,\ ...\\Multiples\ of\ 3:\ 0,\ 3,\ 6,\ 9,\ 12,\ 15,\ 18,\ 21,\ \boxed{24},\ 27,\ ...\\Multiples\ of\ 24:\ 0,\ \boxed{24},\ 48,\ 72,\ ...\\\\24=12\cdot2,\ 24=3\cdot8`

`(5)/(12)=(5\cdot2)/(12\cdot2)=(10)/(24)\\\\(1)/(3)=(1\cdot8)/(3\cdot8)=(8)/(24)\\\\(8)/(24) <(10)/(24) < (11)/(24)\\\\Answer:\ (1)/(3),\ (5)/(12),\ (11)/(24).\\\\24.\\Multiples\ of\ 20:\ 0,\ \boxed{20},\ 40,\ 60,\ ...\\Multiples\ of\ 5:\ 0,\ 5,\ 10,\ 15,\ \boxed{20},\ 25,\ ...\\Multiples\ of\ 10:\ 0,\ 10,\ \boxed{20},\ 30,\ 40,\ ...\\\\20=5\cdot4,\ 20=10\cdot2`

`(3)/(5)=(3\cdot4)/(5\cdot4)=(12)/(20)\\\\(7)/(10)=(7\cdot2)/(10\cdot2)=(14)/(20)\\\\(12)/(20) < (13)/(20) < (14)/(20)\\\\Answer:\ (3)/(5),\ (13)/(20),\ (7)/(10)`