Question

Find the vertex y=x^2-14x+13

Answer 1

Answer: The vertex is (7,36)

Step-by-step explanation:

We are looking for the vertex point (xv,yv) of the parabola. Use the formula for the vertex coordinate xv first, then use that value to oobtain yv:

`y=ax^2+bx+c\\y=x^2-14x+13\\\implies a=1, b=-14\\x_v=(-b)/(2a)=(14)/(2)=7\\y_v=7^2-14\cdot7+13=49-98+13=36`