Answer:
i) Highest velocity at t= 2 s
ii) acceleration is zero at t = 2 s
iii) displacement of the car is area under velocity time graph
Step-by-step explanation:
As we know that the given graph is for velocity time graph
so here maximum velocity velocity is reached when graph will achieve at its maximum height
So it will be at t = 2 s
As we know that acceleration is rate of change in velocity
so we can say
![a = (dv)/(dt)](https://img.qammunity.org/2019/formulas/physics/middle-school/emwr3wviwx3v6hwaf6nm6bd1rcdrvwxsxi.png)
so it is slope of velocity and time graph
so here slope will be zero at t= 2 s
now for displacement we know that
![v = \frac{dx}[dt}](https://img.qammunity.org/2019/formulas/physics/high-school/amx608gv9ss40gdqydpxm0mtdl79y18vvj.png)
![\int dx = \int v dt](https://img.qammunity.org/2019/formulas/physics/high-school/ujomlswjstbh0air5to8w4nq1tvgoxe311.png)
so here we have
![d = \int v dt](https://img.qammunity.org/2019/formulas/physics/high-school/yzzpp5hcqielbro6zuxkdcr3r1sclghnjh.png)
so area of the graph under velocity and time graph will give us displacement of the graph