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Determine the open intervals on which the graph of f(x) = x - 4cos x is concave upward or concave downward

User Madc
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1 Answer

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The graph of the function
f(x) is

  • concave upward, when
    f''(x)>0;
  • concave downward, when
    f''(x)<0.

Find
f''(x):

1.


f'(x)=(x-4\cos x)'=1+4\sin x;

2.


f''(x)=4\cos x.

Now:

1. when
4\cos x>0, the graph of the function is concave upward and this is for


x\in \left(-(\pi)/(2)+2\pi k,(\pi)/(2)+2\pi k\right), \text{ where } k\in Z.

2. when
4\cos x<0, the graph of the function is concave downward and this is for


x\in \left((\pi)/(2)+2\pi k,(3\pi)/(2)+2\pi k\right), \text{ where } k\in Z.

User Franek
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