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From how far on a clear day, and assuming there are no obstructions, could you see from the top of the Eiffel Tower? Take the height of the Eiffel Tower as 300 m and the radius of the earth as 6240 km.

From how far on a clear day, and assuming there are no obstructions, could you see-example-1

1 Answer

4 votes

Answer-

From 61.21 km on a clear day you could see from the top of the Eiffel Tower.

Solution-

From the attachment,

OA = Distance between the top of the Eiffel Tower and center of the earth = 6240 km + 300 m = 6240 km + 0.300 km = 6240.3 km

OB = Radius of the earth = 6240 km

Applying trigonometric properties,


\Rightarrow\cos \theta=(OB)/(OA)\\\\\Rightarrow \theta=\cos^(-1)(OB)/(OA)\\\\\Rightarrow \theta=\cos^(-1)(6240)/(6240.3)\\\\\Rightarrow \theta=0.562

So,


\text{Circumference of the earth} = 2\pi * radius = 2\pi * 6240=12480\pi=39207 km

So, the arc length will be,


=(0.562)/(360)* 39207\\\\=61.21\ km

Therefore, from 61.21 km on a clear day you could see from the top of the Eiffel Tower.

From how far on a clear day, and assuming there are no obstructions, could you see-example-1
User Michael Carman
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