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Blocks numbered 0 through 9 are placed in a box, and a box is randomly picked.

The probability of picking an odd prime number is?
The porbability of picking a number greater than 0 is that is also a perfect square is?

User Bzz
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2 Answers

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A) Since there are 3 (3,5,7) odd primes between 0-9 and there are 10 blocks from 0-9, the probability is 3/10


B) Since there are 3 (1,4,9) perfect squares above 0 and there are a totally 10 blocks from 0-9, the probability is 3/10.

User Ratiorick
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Answer:P(Prime number) = 0.4

P(Perfect Square>0) =0.1

Step-by-step explanation:There is 10 numbers in the box.

Out of the 10 numbers 4 are prime numbers (2 3 5 7) the probability to pick a prime number is thus 4/10=0.4

The only number greater than zero that is a perfect square is 4. The probability of picking a perfect square bigger than zero is thus 1/10=0.1

User Grouchoboy
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