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I need to find sec(theta)= 2(sqrt3)/3

User Pthalacker
by
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2 Answers

3 votes

Ф=11

I need to find sec(theta)= 2(sqrt3)/3-example-1
User Gjois
by
5.2k points
5 votes

Answer: 30° and 330°

Explanation:

sec θ =
(2√(3))/(3)

sec θ =
(1)/(cos(\theta))


(1)/(cos(\theta)) =
(2√(3))/(3)

cos θ =
(3)/(2√(3))

cos θ =
(3)/(2√(3))((√(3))/(√(3)))

cos θ =
(3√(3))/(3*2)

cos θ =
(√(3))/(2)

Look at the Unit Circle to see that cos =
(√(3))/(2) at 30° and 330° ( which is equivalent to π/6 and 11π/6)


User DarkZeros
by
5.2k points