156k views
13 votes
Help !!!
See question in image.
Please show workings .


Help !!! See question in image. Please show workings . ​-example-1
User Eddyuk
by
7.9k points

2 Answers

6 votes

Answer:

see explanation

Explanation:

Given f(x) then the derivative f'(x) is

f'(x) = lim ( h tends to zero )
(f(x+h)-f(x))/(h)

= lim ( h to 0 )
(2(x+h)^2-(x+h)-(2x^2-x))/(h)

= lim ( h to zero )
(2(x^2+2hx+2h^2)-x-h-2x^2+x)/(h)

= lim ( h to zero )
(2x^2+4hx+2h^2-h-2x^2)/(h)

= ( lim h to 0 )
(4hx+2h^2-h)/(h)

= ( lim h to 0 )
(2h(2x+h)-h)/(h)

= lim ( h to 0 )
(2h(2x+h))/(h) -
(h)/(h) ← cancel h on numerator/ denominator of both

= lim( h to 0 ) 2(2x + h) - 1 ← let h go to zero

f'(x) = 4x - 1

User Manishi
by
8.2k points
1 vote

Answer:

4x-1

Explanation:

The working is shown in the above photo

Help !!! See question in image. Please show workings . ​-example-1
User Montrealist
by
8.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories