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2 NaOH (s) + CO2(g) → Na2CO3 (s) + H20 (I) How many grams of water can be produced with 1.85 moles of NaOH​

User Haluk
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2 Answers

3 votes

Answer:

16.65 grams of water can be produced with 1.85 moles of NaOH.

Step-by-step explanation:

Mole ratio of NaOH to H2O = 2 : 1

Number of moles of water = (1/2)×1.85= 0.925 moles

Molar mass of water (H2O) = 18g/mol

Mass of the right water = 18g/mol×0.925 mol=16.65 grams

2 NaOH (s) + CO2(g) → Na2CO3 (s) + H20 (I) How many grams of water can be produced-example-1
User Bjelli
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6 votes

Step-by-step explanation:

Mole ratio of NaOH to H2O = 2 : 1

Moles of H2O = 1.85mol * (1/2) = 0.925mol.

Mass of H2O = 0.925mol * (18g/mol) = 16.65g.

User Rhololkeolke
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4.2k points