Answer:
see explanation
Explanation:
Given f(x) then the derivative f'(x) from first principles is
f'(x) = lim ( h tends to 0 )

= lim ( h to 0 )

= lim ( h to 0 )

= lim ( h to 0 )

= lim ( h to 0 )

= lim ( h to 0 )
← cancel h on numerator/ denominator
= lim ( h to 0 ) 9x²+9xh+3h² ← let h go to zero
f'(x) = 9x²