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What is the equation of a line that is perpendicular to y = 3 x − 2 and passes through the point ( 6 , 8 )

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The slope of the given line is 3. Therefore, the slope of any line perpendicular to y = 3x - 2 is the negative reciprocal of 3, which is m = -1/3.

Starting with the point-slope equation of a straight line, obtain the specific equation applicable here by substituting the givens: m = -1/3, h = 6 and k = 8):

y - k = m (x - h) becomes y - 8 = (-1/3)(x - 6) (answer).

This could, if you wish, be rewritten in some other format.

User Kirill Ermolov
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