Question

Write an equation in slope-intercept form perpendicular to the given equation through the given point

Y = -3x + 4
(6,-2)

Answer 1

y = (1/3)x - 4

Explanation:

Any line perpendicular to the given equation y = -3x + 4 will have a slope which is the negative reciprocal of -3; that is, +1/3.

Start with the general slope-intercept form y = mx + b.

Insert the coordinates 6 and -2 into y = mx + b: -2 = (1/3)(6) + b, or

-2 = 2 + b. Thus, b = -4, and the desired equation is

y = (1/3)x - 4