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A sample of a gas in a rigid container has an initial pressure of 5 atm at a temperature of 254.5 K. The temperature is decreased to 101.8 K. What is the new pressure?

User Lexington
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1 Answer

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P_1/T_1 = P_2/T_2

So

P_2 = P_1(T_1/T_2)=(5atm)(108.1/254.5)=2.12atm

User Dagmar
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