Question

Identify the products in the equation below (the “I” is Iodine—to differentiate capital “I” from lowercase “l”)

2 AgI + Na₂S----------->Ag₂S + 2NaI

Answer 1

Answer : The products are Silver sulfide,
`(Ag_2S)` and Sodium iodide,
`(NaI)`.

Explanation :

The given balanced chemical reaction is,

`2AgI+Na_2S\rightarrow Ag_2S+2NaI`

From the given balanced reaction, we conclude that the 2 moles of silver iodide react with the 1 mole of sodium sulfide to give product as 1 mole of silver sulfide and 2 moles of sodium iodide.

In a chemical reaction, reactants are represent on the left side of the right-arrow and products are represent on the right side of the right-arrow.

Therefore, in a chemical reaction the products are Silver sulfide and Sodium iodide.