2 real roots and 2 imaginary roots
f(x) = (x - 3)(x + 3 )(x-2 + i)(x - 2 - i)
(x - 3) and (x + 3) give real roots x = ± 3
(x - 2 + i)(x - 2 - i) give 2 imaginary roots x = 2 ± i
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