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The model includes a new park in the center of the city. If the dimensions of the

park in the model are 9 inches by 17 inches, what are the actual dimensions of the
park

2 Answers

2 votes

Final answer:

To calculate the actual dimensions of the park, we need the model's scale, which is assumed to be 0.5 inches equals 1 mile. Accordingly, a park that measures 9 inches by 17 inches on the model would be 18 miles by 34 miles in reality.

Step-by-step explanation:

To calculate the actual dimensions of the park, we need to know the scale of the model. Assuming the scale is provided elsewhere, here is how you would calculate it:

First, we identify the scale. Let's say the scale given is 0.5 inches = 1 mile. To find the actual length and width, we multiply the model's dimensions by the scale factor. If the park in the model is 9 inches by 17 inches, we calculate the real dimensions like this:

Actual length = model length × scale factor
Actual width = model width × scale factor

For length: 9 inches × (1 mile / 0.5 inches) = 18 miles

For width: 17 inches × (1 mile / 0.5 inches) = 34 miles

Thus, the actual dimensions of the park would be 18 miles by 34 miles.

User Ekremkaraca
by
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6 votes

The question is incomplete. Here is the complete question.

As a part of city building refurbishment project, architects have constructed a scale model of several city builidings to present to the city commission for approval. The scale of the model is 1 inch = 9 feet.

The model includes a new park in the center of the city. If the dimensions of the park in the model are 9 inches by 17 inches, what are the actual dimensions of the park?

Answer: 81 feet by 153 feet

Step-by-step explanation: Unit Scale is a ratio comparing actual dimensions of an object to the dimensions of model representing the actual object.

In the refurbishment project, the unit scale is given by

1 inch = 9 feet

So, the dimensions of the new park in actual dimensions would be

1 inch = 9 feet

9 inches = x

x = 9.9

x = 81 feet

1 inch = 9 feet

17 inches = y

y = 17.9

y = 153 feet

The actual dimensions of the new park are 81 feet by 153 feet.

User Rafayet Ullah
by
7.6k points

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