Question

When Quinn got home, he turned the air conditioner on. T(t)T(t)T, left parenthesis, t, right parenthesis models the temperature in Quinn's home (in degrees Celsius) after ttt minutes. T(t)=42-0.7tT(t)=42?0.7tT, left parenthesis, t, right parenthesis, equals, 42, minus, 0, point, 7, t How fast did the temperature drop?

Answer 1

Answer: 0.7

Explanation:

Answer 2

We are given

`T(t)=42-0.7t`

where

T models the temperature in Quinn's home (in degrees Celsius) after t minutes

t is time in minutes

Since, we have to find rate of change of temperature

so, we will find derivative

`T'(t)=0-0.7* 1`

`T'(t)=0.7`

So, the temperature drops at a rate 0.7 degrees Celsius per minutes.........Answer