Answer:
r = 1 and r = -5
Explanation:
We are given the following problem with an absolute value equation:

The only variable here is
so we will make it the subject and solve for it.

Isolating the absolute value by dividing the constant -12 by -2 to get:

Setting the quantity inside the absolute value notation equal to a positive and a negative value on the other side of the equation:
and

and

and

and

and
