Question

Solve: Find two consecutive odd numbers such that the sum of the larger number and twice the smaller number is 27 less than four times the smaller number.

Answer 1

Smaller number = 29 and larger number = 31.

Explanation:

Let the two consecutive odd numbers be x (smaller number) and x+2 (larger number).

We know that the sum of the larger number (x+2) and twice the smaller number (2x) is equal to 27 less than four times the smaller number (= 4x - 27). So we can write it as:

`(x+2)+2x=4x-27`

Solving for
`x` to get:

`x+2+2x= 4x-27`

`3x+2=4x-27`

`x=29`

and
`(x+2)= 29+2=31`

Therefore the smaller number = 29 and larger number = 31.

Answer 2

The answer is: 29 and 31.

1. Let's call the smaller odd number:
`x`.

2. Let's call the larger odd number:
`x+2`

3. Based on the information given in the problem, the sum of the larger number (
`x+2`) and twice the smaller number (
`2x`) is 27 less than four times the smaller number (
`4x-27`).

4. Then, you can write the following expression and solve for
`x` to find the smaller number:

`x+2+2x=4x-27\\2+27=4x-3x\\x=29`

5. Therefore, the larger number is:

`29+2=31`