Question

Which of the following is an equation of a line parallel to the line x=3 that passes through the point (-4,-3)?

Answer 1

we are given

a line parallel to the line x=3

It means that line will be vertical line

and we know that slope of vertical line is always infinity

so,

`m=\infty`

`m=(1)/(0)`

now, it passes through the point (-4,-3)

so, we can use point slope form of line

`y-y_1=m(x-x_1)`

we can plug values

`y+3=(1)/(0)(x+4)`

we can cross multiply

and we get

`0* (y+3)=1* (x+4)`

`0=(x+4)`

Subtract both sides by 4

`0-4=(x+4)-4`

`x=-4`

So, the equation of line is x=-4..........Answer

Answer 2

Answer: The equation of a line parallel to the line x=3 that passes through the point (-4,-3) is x = -4.

Solution

The given line x=3 (x=constant) is a vertical line. A line parallel to this line must be a vertical line with equation x=constant, that means the value of x is always the same. Like this line passes through the point (-4,-3) with abscissa x=-4, this abscissa must be constant, then the equation of this line must be x = -4