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What are the roots of f(x) = x2 – 48?
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What are the roots of f(x) = x2 – 48?

User Usta
by
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2 Answers

2 votes

Answer:

Negative 4 StartRoot 3 EndRoot and 4 StartRoot 3 EndRoot

Explanation:

User Edmundito
by
7.8k points
3 votes

to find the roots set the equation equal to zero and solve

0 =x^2-48

add 48 to each side

48 = x^2

take the square root of each side

+- sqrt(48) =x

+- sqrt(3)sqrt(16) =x

x= 4sqrt(3) , -4sqrt(3)

User GabLeRoux
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