Question

What is the equation of a line that passes through the points (-3,2) and (-5,8)

Answer 1

To solve this problem, we have to start with the general formula for the equation of a straight line.

The equation of a straight line is
`y = mx+c`

where
`m` is the gradient and
`c` is the intercept on the y axis.

The gradient is computed by
`m=(y_2-y_1)/(x_2-x_1)=(8-2)/(-5-(-3)) =(6)/(-2)=-3`

The next step is to find the value of
`c` , by picking the point
`(-3,2)` and substituting it into the equation above together with the gradient.

`2=(-3)*(-3)+c\\=>c =-7.`

The equation of the line is

`y = -3x-7`.