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Emaborsa · Answer 1 · 2022-06-08T10:37:10+0000

Answer:

Alkyne

Step-by-step explanation:

The homologous series for this compound is the Alkyne because of the presence of the triple bond present between the third and fourth carbon atoms as seen in the picture attached.

Name the homologous series for this compound and show its structure ch3ch2cc(ch2)2ch-example-1

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