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When 64.0 g of methanol (CHOH) is burned, 1454 kJ of energy is produced. What is the heat of combustion for methanol?

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The heat of combustion for methanol is 727 kj/mol


calculation

calculate the moles of methanol (CH3OH)

moles = mass/molar mass

molar mass of methanol = 12 +( 1 x3) +16 + 1= 32 g /mol

moles is therefore= 64.0 g / 32 g/mol = 2 moles


Heat of combustion is therefore = 1454 Kj / 2 moles = 727 Kj/mol

User Chase Florell
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