Answer:
The value of sin Ф is
Explanation:
In quadrant II, the value of
Let us solve the question
∵ sin²Ф + cos²Ф = 1
∵ cos Ф =

→ Substitute it in the identity above
∴ sin²Ф + (
)² = 1
∴ sin²Ф +
= 1
→ Subtract
from both sides
∵ sin²Ф +
-
= 1 -
∴ sin²Ф =
→ Take the square root of both sides
∵ √(sin²Ф)= ±

∴ sin Ф = ±

∵ Ф is in quadrant II
∴ sin Ф is a positive value
∴ sin Ф =

∴ The value of sin Ф is