79.5k views
5 votes
Vera is using her phone. Its battery life is down to \dfrac25

5
2
​ start fraction, 2, divided by, 5, end fraction , and it drains another \dfrac19
9
1
​ start fraction, 1, divided by, 9, end fraction every hour.
How many hours will her battery last?

User Rufel
by
8.3k points

2 Answers

5 votes

Answer:

3.6 hours

Explanation:

User Yoonie
by
8.4k points
2 votes

We are given that Vera's battery life is down to =
(2)/(5).

Rate of it drain =
(1)/(9) per our.

In order to find the number of hours will her battery last, we need to divide
(2)/(5) by
(1)/(9).


(2)/(5) ÷
(1)/(9)

Let us convert division sign in multiplication and flip the second fraction, we get


(2)/(5) * (9)/(1)

=
(18)/(5)

= 3.6

Therefore, her battery will last in 3.6 hours.

User Rtacconi
by
7.8k points
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