Question

HELP ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer 1

1) (0,-2)

2)
`(-2,0),(-1,0),(1,0)`

Explanation:

The given function is

`f(x)=x^3+2x^2-x-2`

At y-intercept
`x=0`

This implies that;

`f(0)=(0)^3+2(0)^2-0-2`

`f(0)=-2`

The y-intercept is

(0,-2).

At x-intercept
`f(x)=0`

`x^3+2x^2-x-2=0`

Factor to obtain;

`(x+1)(x-1)(x+2)=0`

This implies that;

`x=-2,x=-1,x=1`

The x-intercepts are

`(-2,0),(-1,0),(1,0)`

The points are plotted in the file attached.