Question

Ahmed is working at a butger joint his boss pays him 7.50 per hour and promisses a raise of 0.25 per hour every 6 months which sequence describes ahmeds expected hourly wages

Answer 1

Ahmed's expected hourly wages form an arithmetic sequence starting at $7.50, with a common difference of $0.25 every 6 months. The sequence can be found using the formula for the nth term of an arithmetic sequence: a_n = a_1 + (n - 1) * d, with a_1 being the initial wage and d being the raise amount.

Step-by-step explanation:

Ahmed's expected hourly wages can be described by an arithmetic sequence because he receives a regular raise of $0.25 every 6 months. An arithmetic sequence is a sequence of numbers in which the difference of any two successive members is a constant, known as the common difference. In this case, the common difference is $0.25 per hour every 6 months.

Starting with the initial wage of $7.50, the sequence representing Ahmed's expected wages would be as follows: $7.50, $7.75, $8.00, and so on, with each term increasing by $0.25 from the previous term.

If we denote the initial wage by a1 and the common difference by d, and the number of raises Ahmed has received by n, then the nth term of the sequence (an) representing his wage after n raises can be found using the formula an = a1 + (n - 1)*d. In this scenario, to find Ahmed's wage after a certain number of 6-month periods, you would substitute a1 = $7.50 and d = $0.25 into the formula and calculate the resulting wage.

Answer 2

Hourly wage = $7.50 + (0.25 x 6m)

Ahmed starts off at $7.50 an hour. You would add $0.25 an hour every 6 months. m = the number of times 6 months has passed. So the 1st 6 months m=1, the 2nd 6 months m=2, etc. For the time between Ahmed's start date and his 1st 6 months, m=0.