Question

Can someone please help me solve an Algebra equation?

Direction: Write each equation in *standard form*.


`(3)/(5)x+ (1)/(4) y=-(1)/(2)`

Answer 1

bearing in mind that

standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient

now, to do away with the denominators, we'll multiply by the LCD of all fractions, in this case 20.

`\bf \cfrac{3}{5}x+\cfrac{1}{4}y=-\cfrac{1}{2}\implies \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{20}}{20\left( \cfrac{3}{5}x+\cfrac{1}{4}y \right)=20\left(-\cfrac{1}{2} \right)}\implies \stackrel{\textit{standard form}}{12x+5y=-10}`