Answer:
V₂ =1.99 L
Step-by-step explanation:
Given data:
Initial volume = 1.8 L
Initial temperature = 28°C (28+273.15 K= 301.15 k)
Initial pressure = 102 KPa
Final volume = ?
Final pressure = 85 KPa
Final temperature = 4°C (4+ 273.15 K = 277.15 K)
Solution:
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
V₂ = 102 KPa × 1.8 L × 277.15 K / 301.15 K × 85 KPa
V₂ = 50884.74 KPa .L. K / 25597.75 K.KPa
V₂ =1.99 L