Question

2c2h2(l) 5o2(g) yeild 4co2(g) 2h2o(g) if the acetylene tank contains 37.0 mol of c2h2 and the oxygen tank contains 81.0 mol of o2, what is the limiting reactant for this reaction?

Answer 1

o2

Step-by-step explanation:

Answer 2

2C2H2(l) +5O2(g)→ 4Co2(g) + 2H2O

The limiting reactant for reaction above is O2

explanation

The limiting reagent is determined using mole ratio of both reactant.

that is the mole ratio of C2H2:O2 which is 2:5 .

The mole ratio above implies that 37.0 mole of C2H2 needs 37.0 moles x5/2=92 moles of O2.

Since the available moles of O2 was 81.0 mole and 92 moles are required to completely react with C2H2 , O2 is the limiting reagent.