We are given

where
x is width of rectangle
A is area of rectangle
Since, we have to maximize it
so, we will find it's derivative
and then we can set it to 0
and then we can solve for x


now, we can set it to 0
and then we can solve for x


So, width is 12 feet
Maximum area:
we can plug x=12


So, the maximum area is
................Answer