Question

Kyle and Michael run a lap around a track. Kyle gets a 50 meter head start and runs 3 meters per second. Michael runs at a speed of 4 meters per second. How long will it take for Michael to reach Kyle

Answer 1

First, you need to put both equations in slope intercept form

Kyle: y=3x+50, because he runs 3 meters/second and he gets a 50 meter head start

Michael: y=4x

I think the answer would be 50 seconds

hope this helps

Answer 2

50 seconds

Explanation:

Let x be the distance ( in meters ) from kyle to the point where they meet.

Since,

`Time =(Distance)/(Speed)`

For kyle,

Distance = x,

Speed = 3 m/s

So, time taken by Kyle =
`(x)/(3)`

Now, for Michael,

Distance = (x + 50) ( Because Kyle is 50 meters ahead of Michael )

Speed = 4 m/s

So, time taken by Michael =
`(x+50)/(4)`

When they meet each other,

`(x)/(3)=(x+50)/(4)`

`4x=3x+150`

`x=150`

Hence, the time after which they meet =
`(150)/(3)` = 50 seconds