Answer:
![310.5(miles)/(hr)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/xzuonx5zoox4i65lfwh55eapyf6ss1wkia.png)
Explanation:
Earth's movement around the Sun is constant, so its expressed by:
.
However the problem is asking the speed in miles per hour, to do that we need to transform the time from years to hours.
We know that 1 year equals 8760 hours. Then, we replace all values in the equation and isolate
:
![d=vt\\v=(d)/(t) \\v=(2.72x10^(6)miles )/(8760hours) = 310.5(miles)/(hr)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/tlndhg2c5x67ha2e62g0mavjfw7k2s8xvj.png)
Therefore, the speed of the Earth around the Sun is
![310.5(miles)/(hr)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/xzuonx5zoox4i65lfwh55eapyf6ss1wkia.png)
PD: million is equivalent to
![10^(6)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/wv3hi7jstn50e4qntxqqzrb3ig03k7xgzx.png)